tests - Solution for Mid Term Test Question 1: a. r = (71)...

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Solution for Mid Term Test Question 1: a. r = 2 . 521 (7 - 1) 4 . 6667(0 . 0388) = 0 . 9874 Since it is close to +1, we have a strong positive linear association between T and S . b. b = 0 . 9874 q 0 . 0388 4 . 6667 = 0 . 09, and a = 1 . 792 - 0 . 09(4) = 1 . 432 Therefore ˆ S = 1 . 432 + 0 . 09 T For each year, the predicted sales increased by $0.09 millions. c. For year 2010, we have T = 16. Therefore ˆ S = 1 . 432 + 0 . 09(16) = 2 . 872. Hence predicted sales in 2010 is $2.872 millions. No, we should not trust the result because we are extrapolating. Question 2: a. min = 25, and max = 130. Q 1 = 2 . 75 th smallest number = between (30 , 33) = 31 . 5 ˜ x = 5 . 5 th smallest number = between (39 , 53) = 46 Q 3 = 8 . 25 th smallest number = between (69 , 94) = 81 . 5 Hence the simple boxplot can be drawn. b. IQR = 81 . 5 - 31 . 5 = 50 1 . 5 IQR = 75 Inner fence = (31 . 5 - 75 , 81 . 5 + 75) = ( - 43 . 5 , 156 . 5) Since all data are inside the inner fence, there is no outlier nor extreme outlier. Question 3:
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This note was uploaded on 12/22/2010 for the course MATHEMATIC Math 1131 taught by Professor Augustinewong during the Spring '10 term at York University.

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tests - Solution for Mid Term Test Question 1: a. r = (71)...

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