# tests - Question 1 a Let X be the number of homes(out of 6...

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Question 1: a. Let X be the number of homes (out of 6) in Riverband area of Edmonton that have a security system. Then X Binomial (6 , 0 . 4). Therefore P ( X = 3) = 6! 3!3! (0 . 4) 3 (0 . 6) 3 = 0 . 27648 b. See the table below and we have the mean is 1110 and the standard deviation is 24900 = 157 . 80. Admissions Probability xp ( x ) ( x - μ ) 2 p ( x ) 1000 0.6 600 7260 1200 0.3 360 2430 1500 0.1 150 15210 1110 24900 Question 2: a. minimum = 510 and maximum = 970 Position of Q 1 = (36 + 1) * 0 . 25 = 9 . 25 Q 1 = between Position of ˜ x = (36 + 1) * 0 . 5 = 18 . 5 ˜ x = between Position of Q 3 = (36 + 1) * 0 . 75 = 27 . 75 Q 3 = between IQR = 875 - 735 = 140 Inner fence = ( Q 1 - 1 . 5 IQR, Q 3 + 1 . 5 IQR ) = (525 , 1085) Since all data points are within the inner fence, then there’s no outliers and the boxplot is just the simple boxplot formed from the 5-number summary (510 , 735 , 820 , 875 , 970). b. No. Empirical Rule should applied to only “bell-shaped” distributed data. From the

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tests - Question 1 a Let X be the number of homes(out of 6...

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