chap85 - Belt Friction Let's look at a flat belt passing...

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Unformatted text preview: Belt Friction Let's look at a flat belt passing over a drum Let's take a look at a differential element Motion is assumed to be impending. dN dF s = The normal force is a differential force because it acts on a differential element of area. 2 cos ) ( 2 cos = + +- - = d dT T dN d T F s x 2 sin ) ( 2 sin = + +- - = dN d dT T d T F y For small angles cos( d ) = 1 sin( d ) = d = + +-- dT T dN T F s x dN dT s = T 1 P P ' d P 1 P 2 O dN d s dN T+dT T d /2 d /2 x y r 2 ) ( 2 = + +- - dN d dT T d T F y 2 2 2 = + - - - dN d dT d T d T 2 = d dT (2 small numbers squared = 0) Thus: d T dN = Substituting: d T dT d T dT s s = = Integrating: d T dT O s T T...
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This document was uploaded on 12/23/2010.

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chap85 - Belt Friction Let's look at a flat belt passing...

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