Diesel Cycle Notes

Diesel Cycle Notes - C E H E pd m m 3.4 O H BRYAN TEXAS m MECHANICAL ENGINEERING fl&,5 M f“ 715 M#2(am/4M5 5129 5792/66 I v’ 3 5,1114

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Unformatted text preview: C) E H E pd m m 3.4 O H BRYAN, TEXAS m MECHANICAL ENGINEERING , . fl,&/ ,5 M f“ 715/ /% M; #2. (am/4M5 5129/, 5792/66 , , I v’ 3. 5,1114%! a”! ,«ia‘fla’? 7”“ch m 7: €an 1 —> L AJ-‘m‘oak‘c Cwylowc» 3‘») 3 cenwgvm'i ‘x‘maé caulk" 3w mirva fix WSW lei—9a grim M4 N1? Am», I . , l g €Uflé¢u¢¢‘ zlnigy’ 294,44] rupw fifrrwgfi Far'~'i"1-e' Wei Mar : arm *’ (E‘s-we $1 macaw/WM dd! Em cméu§7lv34 a 'm I 3 v‘ A h .7 , . / , , “WHEN”,Ema/M.-. Vq = V: yj‘ : _,l i *3 V7. Va) * If Fseava‘L (Vac/s; 3’ 6M% “(44%) Mai, E ; E m3 #3 U‘Jl‘flé Cum aw 5U. Woiflsw'x ’VA z i 3 Ti V1] ‘ , - Céw} xii/mi”; “5’17. Map! r9 \4” \ I QC” 0 DE-L'WW WPO‘LJP :1 (ML Frwcl‘w! stark: Cficj‘fi' I“! had \lgol .3 1-7: :69?) " r I“ Tv’T\ V ‘ ‘é'qré R TI —2 Ewaaer‘m @963 it - .Vgrié .ivi VL ., ,,.r..__. +11,"va vmgg 13— k— I ’59. - 13. = T» :‘Y’3 V" T3- > I (J V25! chuck'r MEC?(’E’TL) “CV flw‘Tt) M: 3:25. .WQLBWQLF ; my»; 4:... RT‘ (qufia (no) $71 5 044‘! 22 H: ER“ 53% a; 8m m MECHANICAL ENGINEERING ’u {we} TML‘ pb‘ s L“ON/4k) AZ} 0443 I ,1”: ‘Vi/Vz‘f 20 R 7&0!) ER. AH?" SH T]: “520 K. 6W» (D T‘ 5 3%) K ) U.= (Sm-60; “A? 3 ’67. : waxy [email protected]\f2_.£€ -VL~¢.L —,=v mu VA-wrflWCMfl/fi-L/JW 472 ,J flaw 4. “9 79’ //35~7 0/? ) A; = My? kg. 55% 6) .—. A; “A; ,; [,3 ; gag/2‘ = 2102.59 LA”? Wm»... E” 53"} 7;=/?’7‘/.§/4, 45%: 3.47202. 54f; @ Imfifiw mfmw .yi-fi¥3fifiz;zigy +4)" *4 9: V2. 7%) MN Lat/5'? w 57 J: W3 3 '3 Wu fl #5 3‘ My: 9!]. 5U! flflN .7671 #7; 423/ (DU) E2 ,K :7; = /§’51~7,5/< 5F: y 094 +P=,1:j;; W495" 5 Fm L} V2. 1‘» Has/a “' M + w= 353,25 : (Ia—waqu =~ W0 " Kazan/yr'v 99/. 59} a W 393,5” A? Md «- 5%,: “A? ,d “xwwm‘v “,‘v 2m ma é: Fan WP: /ot«/7 ///3- Wow—3M q-zz Mu: Acolak afr—si-amdavA Diem! c\e \NLS a. jcnéwn compression. rafio «MA 0. specif—I‘QA s {auda-k- flu. beslnm‘ns of' comprecnbvu. 1"“ WWkMkM “gale. finger-am is given. 12mg: Dzkrm'm (0») Ha “9+ Work ,Qo) MMVMqA aFFu'cniu , (c) ‘HM. Mum d—Fed-we (wresmumnok (d)+h¢'cu+09€— 1’ Ho. C E NRC QUE“) D '. T. 3‘ a 9% V-Nz =“' I I air : - --_-i a a 14.0 MIME Agggmgflogs: See. Example. ?.7.. A450, assume amsmt Specific heats eValqM-ed at 520% Mmysts: My, ae+armme m ampmm we‘mu pnaa‘pal sMe (9'9 HM. aide. 1;: 520°R owL& T3 = 4000‘]; are 3Wew. sfljg 2.: Forwas'eutupué. cvmpresmb-w,wm« k=w01 ‘vaTableAfloE T,_ =(V'/v.,_) "T. was “K Sj-fieS: Sllivnlarlg ,-Por‘ Hue. eacpaMuolw _\_/_.._ _ v. V v T (IQ-b v, — = =01) thaw-5833 n = «warn = m (a) For Hit-1cm, Wald. = Quick. ‘rkus W‘flde = avg-QM: " m}: Cpc'rs'T-g) - CyCT’..-T.)] Evaluafikfl m m _ 11v. _ w.o\w.-.e.\( 2.4+ [14+ ‘33:, o s“ u, ' RT, ' [5 s .M “‘ 4“ (afi‘fi'ififrz 5‘5")" * ‘ H‘ 3) R3 Ms,w‘r\4« cP= 0.2.40 Bwlb-WL wwl cur—own smith-"z m4 wu‘de = (-NSH) [c.mouqooo —lem)— (.nm lwas- 520)] = so.” BM‘_____________—Wg11¢_ (b) 11w. Mrm\ efi'xcfenas Ks = M ._ _&1&_ __. (5040 K Q23 ween; ~13.) (“90(an (H000 41,194) ‘ -"° 3 (5°55 %)‘__V\ (q The. mama oM-uwve pressure {3 _ wfl“! Wfit‘! “*9 ‘ ‘fo-V: ' V\(‘-VZIV|) _ (SOJIBM) 113 H4“ ME — (2H3)(|-'/H\l IBM “Hun/F: “433 ‘5’“0‘54—‘1‘1‘3 (A) r¢=Vs/v,: T3171 = Woo/max. = 2.474_______v‘5_ 9'37 PEOBLEM q . 23 10600453: Pm air-SMMMM '{h‘esd de. hasa known Companion. ‘ rad-i0 MM « spec-SIGMA 5432 wt m befliuhing o-F wwpresswn. The head. add'va fer uwdd' Mass is given. 13¢“!an U») '1'“ wrung/m fimperijumgl (b) Maud-9H VINO] (a) m “1- wart: perum‘f- II“ mu , (d) {Amy-MA gffva-enc (3) .1»... mm e-Huth [Manure . (f) Piaf 1—qu 1Vdn‘lu‘l'l‘P-l versus compassion wuh‘o. ‘ ~‘ FUND: I c We“ DA’M = Assuupnons: See Example 9.7. MIX. Begin by #fxn'nj each fru'ndpal shade of +er. udclel’ETaGle/i- 22) 5mm I : T; = 380K u, = 271.0"! kT/kg , u}. = 3"14 my. For +ke {Scwhopc'c compresaim Un=(‘$’f]vfl = (550) MM = 17.17 11m, T1=I1351°R , kl: 1202.0 nun, shun 3'. For HM. head- addl‘I-w'u frocess , 024/.“ = ‘43-‘41. 'l‘lww k3: azalm+ M.‘ = 1102.0 kirllca 11mm, T, “811.5 K M12}, - 5.92.02. S‘aig H: For Hm isewH-opir. expmum'om y—"=v'-Yé =\£L.Tz vs V;- v3 V7- T3 = 12.08 0W1 rum 4‘93.) «1;, = qlfbl‘p W8 Tu: 8q3fl K , u‘, = 4.23.11 kI/kg (A) Tb. mimumwmm in Mu. add: is T3: )6'1‘15 K a Tum: 0" “For ‘Hm CAM-SM 'pressure frocecs V r=_3_=T3_l8‘H.S _ 6 r e V:— T2. " “35.2. - l' 6"“ "‘ ‘ (0 Form «3:44., Waxy-14 -— 62%. Thus W \e 1 *3;— - QT:- - 9% =(k3-M—(uu—ul) I‘nserh'ng values wcfmdc k z 900 kslkj —(bL8.11—21l.(9‘l)ulkj flasks/25w 9—38 PROBLEM c1.7.3» (Can-Pd - PagL 2) (d) The “dermal cFFidenaj is VL = Wade (m __ 543.5 st (M ‘1 00 (e) The meom eH-eche yresswre is ngcle = Winch/M = 0.604 (60.4 0/0) = 10461 kPa.‘_________—___Vieg (Hm: dab: .fior Mae rewind rial-s ave oblm‘ued us'wg LT, as Follow-‘1 IT Code p1 = 200 I/ kPa T1 = 380 l/ K 023 / m = 900 // kJ/kg m = 1 // Assume a unit mass of1 kg. P3 = P2 v4 = v1 r = 20 v1 = v_TP("Air",T1, p1) s1 = s_TP("Air", T1, p1 ) u1 = u_T("Air", T1) r = v1 /rv2 v2 = V_TP("Ail'",T2, p2) 52 = s_TP("Air", T2, p2) 52 = 51 023 = m * (h3 - h2) h2 = h_T("AiI", T2) h3 = h_T("AiI“, T3) 53 = s_TP("Air', T3, p3) v3 = v_TP("Air",T3, p3) u3 = u_T("Air", T3) v4 = v_TP("Air",T4, p4) s4 = s_TP("Air", T4, p4) s4 = 53 u4 = u__T("Air", T4) rc=v3lv2 chclelm = QZ3/m - (u4 - u1) eta = chcle / 023 mep=chc|e/(m *v1*(1-1/r)) IT Results for r = 20 u1 = 271.5 kJ/kg T2 = 1135 K [)2 = 11950 kPa hz = 1201 kJ/kg ha = 2101 kJ/kg T3 = 1881 K T4 = 844.1 K p4 = 444.3 kPa u4 = 628 kJ/kg rc = 1.657 Wows/m = 543.5 kJ/kg n = 0.6039 mep = 1049 kPa ‘i ’3? map = Vr‘Vz. 1r, (1- valv.) Usuins -Ha¢ [deatga-S fiaahicm af- shad-e, z RT. = %g%£%\(380|<) we. “um”. I 7‘ (Zoo kPa.) |<>§NIM1 NJ I = 0.5t155 MB/kg Thus, +he mep becomes ( 543.5 Icing) losu-w. Itch. mp=———-——- ——u—.—-:; (0.9453 mB/kom— {15) 11:7 Io ulm ...
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This note was uploaded on 01/03/2011 for the course MEEN 315 taught by Professor Ramussen during the Fall '07 term at Texas A&M.

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Diesel Cycle Notes - C E H E pd m m 3.4 O H BRYAN TEXAS m MECHANICAL ENGINEERING fl&,5 M f“ 715 M#2(am/4M5 5129 5792/66 I v’ 3 5,1114

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