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Unformatted text preview: 3-34E Left chamber of a partitioned system contains water at a specified state while the right chamber is evacuated. The partition is now ruptured and heat is transferred to the water. The pressure and the total internal energy at the final state are to be determined.AnalysisThe final specific volume is /lbmft5.1lbm2ft33322mVvAt this specific volume and the final temperature, the state is a saturated mixture, and the pressure is the saturation pressure 4E)-A([email protected] 2psia67.03PPThe quality and internal energy at the final state are Btu/lbm38.460)25.830)(2299.(51.2692299./lbmft)01745.4663.6(/lbmft)01745.5.1(223322fgffgfuxuuxvvvThe total internal energy is then Btu920.8)Btu/lbm38.460)(lbm2(22muU3-35 The enthalpy of R-134a at a specified state is to be determined. AnalysisThe specific volume is /kgm03.kg300m933mVvInspection of Table A-11 indicates that this is a mixture of liquid and vapor. Using the properties at 10°C line, the quality and the enthalpy are determined to be kJ/kg180.02)73.190)(6008.(43.656008./kgm)0007930.049403.(/kgm)0007930.03.(33fgffgfxhhhxvvv3-36 The specific volume of R-134a at a specified state is to be determined. AnalysisSince the given temperature is higher than the saturation temperature for 200 kPa, this is a superheated vapor state. The specific volume is then state....
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- Fall '07
- Thermodynamics, kPa, total internal energy