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# titration - them to get moles. Once you get moles of...

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Chapter 3 Stoichiometric Problems Titration Problems: If it takes 30 ml of .3 M NaOH to exactly neutralize 50 ml of H 3 PO 4 , what is the M of the acid? Rather then dimensional analysis, consider just multiplying M X V to get moles. Then change moles of NaOH to moles of acid from the relationship of the coefficients in the balanced equation. At this point, just plug in moles and liters into M = moles/L for the answer. If student realize that anytime they see M and V, it is probably so they can multiply
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Unformatted text preview: them to get moles. Once you get moles of anything in the equation, it can be changed to moles of anything else in the equation by using the stoichiometric relationships. TWO MAJOR CONCEPTS: M X V = moles Change Moles of one thing to moles of another by using the balanced equation. 3NaOH + H 3 PO 4 Na 3 PO 4 + 3H 2 O M X V = .03 L X .3 = .009 mole NaOH (.009 mole NaOH/1)(1 mole H 3 PO 4 / 3 mole NaOH)= .003 mole H 3 PO 4 M = moles/L = .003 mole H 3 PO 4 / .05 L = 0.06 M H 3 PO 4...
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## This note was uploaded on 01/03/2011 for the course CHEM 1442 taught by Professor Rogers during the Spring '08 term at UT Arlington.

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