labbenium - number 39) the calculation is as follows. % of...

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Beanium Using various beans, determine the atomic mass of the new element Beanium. Solving the problem: If a student counts 39 red beans (mass number 35) and 102 white beans (mass
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Unformatted text preview: number 39) the calculation is as follows. % of red = 39 / 141 X 100 = 28% % of white= 102 / 141 X 100 = 72% Atomic Mass = (.28 X 35) + (.72 X 39) = 37.9 amu...
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This note was uploaded on 01/03/2011 for the course CHEM 3302 taught by Professor Dickpowell during the Spring '10 term at UT Arlington.

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