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Unformatted text preview: 1. Solve 2x 2 =6. Find the x intercepts of f(x) = 2x 26 x 2. Need exact and approx solutions. (x8) 2 =25 3. Need exact and possible solutions. Y 210y+25=36 4. Solve X 216x=10 5. X 2 +6x27=0 6. Solve x 2 +7x7=0 and find the x intercepts of f(x)=x 2 7x7 7. If a b ball player has a vertical leap of about 25 inches, what is his hang time? Use the hang time function of v48 t 2 Given: V=48t, V = 25 25 = 48t 25/48 = t (25/48) = t 0.72168 sec = t 8. X 2 +12x+4=0 x^2+12x+4=0 x=[12+sqrt(14416)]/2=[12+sqrt(128 8*sqrt2]/2=6+4sqrt2 x1=6+4sqrt2 x2=64sqrt2 9. R 2 +3r=3 10. Solve 3x 25x13=0 and find x intercepts of f(x)=3x 25x13 3x^2  5x  13 = 0 3x^2  5x = 13 x^2  (5/3)x = 13/3 x^2  (5/3)x + 25/36 = 13/3 + 25/36 (x  5/6)^2 = 161/36 x  5/6 = 161/6 x = (5 161)/6 The xintercepts of f(x) = 3x^2  5x  13 are (5 161)/6. 11. 2(x4)(X+2)=(X+2)(X4) (x+2)(x4)2(x4)=(x+2) (x4)[(x+2)2]=(x+2) (x4)x=(x+2) x^24x+x+2=0 x^23x+2=0=>(x2)(x1)=0 =>x1=2 =>x2=1...
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This note was uploaded on 12/30/2010 for the course DSA 12 taught by Professor Jhonecaine during the Winter '10 term at Aberystwyth University.
 Winter '10
 JhoneCaine

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