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Unformatted text preview: d (n+1) = 0.25(101) = 25.25 k is the greatest cumulative frequency less than or equal to 25.25, which is 22 X k is the upper limit of the class containing 22, which is 18 h is the next higher cumulative frequency, which is 46 X h is the upper limit of the class containing 46, which is 20 Therefore, substituting the values we have P 0.25 = 18 + ( 25.25 22 )( 20 18 ) = 18.27 ( 46 22 ) If we want to find the median, then we put d = 0.50 and proceed as above. It is the same for any other percentile, e.g. 70 th or 65 th etc....
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This note was uploaded on 12/30/2010 for the course BUSS 202 taught by Professor Ritageutchian during the Three '10 term at Notre Dame AU.
 Three '10
 RitaGeutchian

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