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sampling_distribution

# sampling_distribution - Nisreen Khalil 600,500 550 Nisreen...

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Sampling distribution Sampling distribution of the sample mean Population Data Students GMAT scores Nada 600 Khalil 500 Diane 700 Nisreen 600 =ΣX/N =(600+500+700+600)/4=600 =(0+10000+10000+0)/4=5000 a) All possible samples of size 2 taken WITH REPLACEMENT: Possible samples Scores Distinct Nada, Nada 600,600 600 500 =1/16 =500*1/16 625 Nada, Khalil 600,500 550 550 =4/16 =550*4/16 625 Nada, Diane 600,700 650 600 =6/16 =600*6/16 0 Nada, Nisreen 600,600 600 650 =4/16 =650*4/16 625 Khalil, Nada 500,600 550 700 =1/16 =700*1/16 625 Khalil, Khalil 500,500 500 16/16=1 μ =600 Khalil, Diane 500,700 600 Khalil, Nisreen 500,600 550 Diane, Nada 700,600 650 Diane, Khalil 700,500 600 Diane, Diane 700,700 700 Diane, Nisreen 700,600 650 Nisreen, Nada 600,600 600

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Unformatted text preview: Nisreen, Khalil 600,500 550 Nisreen, Diane 600,700 650 Nisreen, Nisreen 600,600 600 μ X σ 2 X =[Σ(x-μ) 2 ]/N σ 2 =2500 ) ( . X P X ) ( X P ) ( . ) ( 2 X P X X μ-X X X X Sampling distribution b) All possible samples of size 2 taken WITHOUT REPLACEMENT: Possible samples Scores Distinct Nada, Khalil 600,500 550 550 2/6 550*2/6 833.33 Nada, Diane 600,700 650 600 2/6 600*2/6 Nada, Nisreen 600,600 600 650 2/6 650*2/6 833.33 Khalil, Diane 500,700 600 6/6=1 μ =600 Khalil, Nisreen 500,600 550 Diane, Nisreen 700,600 650 σ 2 =1666.6667 ) ( . X P X ) ( X P ) ( . ) ( 2 X P X X μ-X X X X...
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