Final-Summer-2004-Abu-Khuzam-Lyzzaik

# Final-Summer-2004-Abu-Khuzam-Lyzzaik - 16'693 a Q—-3...

This preview shows pages 1–11. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 16'693 . a Q— -3 ‘— 13.:13‘. 14.3004 MATHEMATICS 20-4 NAME ................. -_ ‘_“e : '2. Hours FINAL EXAMINATION 113,—“; ———————————————— -- W“ \ Summer 2004 Circle your section number : 1 (10:00, Dr. AbU'lﬂluLdLil) 2 (1 1:15: D11 Abu-Klmzam] 3 ( 8:45 , Dr. Lyzzaik) PROBLEM GRADE PART} 1 ..... -_ ,1 a 2 ..... -- s 3 ————— w 7 4. ----- —— s 5 FFFFF __ 13 PART II 6-20 ..... —— TOTAL. ————— -— so -._._.—.-I--—"" lgnu‘s ,\ Q \ WEhsI‘T‘h L l B i: A R Y or mama-I C ‘- PART 1. Answer each of the following problems in the space provided for each pi’oblem ( Problem 1 to Problem 5). (40 points) 1. One card is to be drawn at random from a deck of 5’3 cards. Find the probability of selecting an ace or a bean. [ 4 points] .1 2. Lei fog/1:) 23:3 + x' points. — 3): + 61 +10 , Delemiine the location and nature of all critical [ 8 points] (3) Find f): (b) Flnd f 1 (0) Find f” II R l f . . __ 2 “.Le‘ J (Adi) —5.1’ 111 34141:? +9. [ 2 points] [ 2 palms} [ 3 points] L 4,‘ Sketch and ﬁnd the area 0fthe region bounded by the parabola j' = 4 — A" and the line f." = 3x . [ 8 points] K. , A 1 ‘ th'aluats the folmwmg unegrais. - (a) J4JV€VL d): i 4 pOXIItS] [ 5 points] PART II. Circle the correct answer for each problem of part B ( Problem 6 to Problem 20) in the TABLE PAGE 1. [4 points for each correct answer; -1/2 point penalty for each wrong answer]. (60 points) [’1 o 0‘ 6. Let A:l0 l 0 .Then {1 o —1) (a) A': =A (b) A9:A (c) A9 : 0 (zero n‘ratrix} (d) A is no! invertible (e) none of the above [4 points] 7. The number of ways in which 3 persons can be chosen from 10 persons so that one is a chairman: the second 15 a vice chairman and the tlnrd 15 a secretary is. (3) 10C; (b) 10:“ (C) 20133 (Ell 3”: (e) none ofthe above [4 nouns] (6) none ofthe above 1_ 4 poner ‘“ ‘l/zi: ‘5‘ iii/1 (e) none of the above [ 4 points] (6] none of the above [ 4 points] ’3 i A box contains in mathematics. books and 4 1115101? books. 4 books are. Lo be seiected at random from the box wmhoui replacement. \N-"hai is the probability mat the fll‘Sl book \x‘i'l‘i be a iiiatheiiiaiics book and the see id and third are illSiOi'}-‘ books? (a) 'J 4 I (b) i: ‘ “ Ci 0,}. , (d) O“: 1 ii A far; coin is to be dipped few times The. probability that exactly 5 heads will occur is: {a} 0.5- “ _ {L} 0.: (C‘) 06??" (d1 0 75 {:1 none oz'fne abO‘ce 4 13011115] ‘r X — 57 Then {WU} is aqua] u): 30 (d) 5‘0 (e) none ofthe above [ 4 points] 14,1,er _]r()c_.}.';} :— 21" I . ‘ .' 3 -" — 5}: . Then the point (1.2-4) is: {at} a relative mmunum pouu ‘ j a relanve maximum poun (c) a saddTe point (d) none ofthe above [4 points] (1 . . . r . r ‘ » 2 - . . . 1:. The esumated Value of the deﬁmle mlegra; — ﬂair usmg the trapezordal rule wnh 11:41. (subdividing into 3 equal sublntervals) i5. :9 r] E [4 points] 16.. The marginal c051 (in dollars) ofproducing a product is .MC = 83’ -r 800 r where A’ is the number of products produced. It is known that {he lota‘i cost equa'is 5:60:000 when 40 units are produced (it: C(ﬁk }=60000'I. Then The 101a} 8051 funcuon is 1 Cm: deﬁne; or: grew—41.500 cm: 1A3~800x+80,000 Cm: 4x2—800x-L21.600 none ofthe above [4 points] \ 1“: h... | O — 2 I Then the detennmam ofthe matm ofcofaclors AC 15 equal to: O 0 j? (E14) 4 (b) 72 (c) 16 (d) 64 {e} none ofthe abmre [ 4: points] (a 27 CW 1 3g 3h 31' 18‘ 1f A=‘ (4" (-3 f . suchthat \Ai=3:tl1en j3a+d 3b-‘-€ 3C+f§ is equalio: i r ' Q \g h z/J ‘ 5a SE) .;C ‘ (at 15 (b) 3:35 (c) -45 (d) 45 (6) none of the above { 4 points] 19 Giver. a random variable X which as nonnally distﬁbuted , with mean u =130 and Standard deviation 0‘ = 5‘ . The probability P (128 < X <142) is; (a) 0.1824 (b) 0.519 (c) 0. (d) C'. (e) (7)1 '1‘ ON I\ M I.) w Q u: m '1: [4 points} 20. Let : 111(k).) + 2x *1). Then is equa] 10' (all I (b; 2 {C} G (d) 3 O (57 none ofthe above { 4 points] e u C :m m 0 N 15 r a .d n a ..L S B rea Under Lb. j __.'1 ...
View Full Document

## This note was uploaded on 01/02/2011 for the course MATH 204 taught by Professor Romyarbid during the Three '10 term at Notre Dame AU.

### Page1 / 11

Final-Summer-2004-Abu-Khuzam-Lyzzaik - 16'693 a Q—-3...

This preview shows document pages 1 - 11. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online