hw7_sol1

Hw7_sol1 - p360 E = 200 GM Brass shall “a" E = 105 CPa j ‘5 brass shall(523’5233 X 19 isrfiflly 235mm te tbs gm><

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Unformatted text preview: p360 E = 200 GM Brass shall “a " E = 105 CPa j ‘5 brass shall (523’5233 X 19%;?) isrfiflly 235mm te tbs gm ' >< 1_G_5/9F).’/De}:¢finine the largeStifiloWablc increase in tem- straw the 53663 can: as: tr; 55 MP3. ’ “Wm O 6:} 40 in. 2"? gig»: i») 5“) 7 /;-in. 1% a diameter 2.52 A rod consisting of two cylindricai poriéons AB and BC is re— strained at both ends. Portion AB is made of brass (Eb = 15 X 106 psi, ab = 11.6 X 10“???) and pertien BC is made: of gigs} (E5 = 29 X 106 psi, as = 65 X IO'GPF). Knowing that the rod is initiaiiy unstressed, determine (a) the normal stressss induced. in pardons AB and BC by a temperature rise of 90°F, (12) the: carresponding deflaction of pain: 8, “a f I fix, a g i i a 2.50 A: room temperature (ZOQC) a 0.5—mm gap axis of me mds shown A: a later time determine (a) the norm-a1 stress, in the aluminum rod, (12‘) t of the. aluminum rod. ()5 mm f<—-—~ 300 mm HA—vlfkmvfi‘) mm 1 ' 1 l -flwfi“! * Stainless steel Alnn’finum A = 7000 mm2 A = 800 man E 3 73 31311 F = 190 CPR a : 17A13>< MY ~ 23 >< lO'fi/OC Ky, Wm when the temperature ha is betwaen the ends. 3 reached MOOQ he change in length B1°C my, ‘ aflwflmk , ...
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This note was uploaded on 12/30/2010 for the course CE 3400 taught by Professor Moorthy during the Fall '09 term at LSU.

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Hw7_sol1 - p360 E = 200 GM Brass shall “a" E = 105 CPa j ‘5 brass shall(523’5233 X 19 isrfiflly 235mm te tbs gm><

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