10_MAE 334Woodward - lab5

10_MAE 334Woodward - lab5 - transfer function? Results...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
MAE 334 – LAB 5 10 Single Pole Low Pass Filter Sine Wave Input Response 0.0 0.2 0.4 0.6 0.8 1.0 1.2 0 5000 10000 15000 20000 25000 Frequency (Hz) Amplitude Ratio (Vout/Vin) 5. Plot the raw data voltage vs. time the filter input and output signals. These should be on the same plot. Zoom in on the time near the step input to better visualize the differences. Low Pass Filter Step Input Signal and Response -0.6 -0.4 -0.2 0 0.2 0.4 0.6 0 0.0005 0.001 0.0015 0.002 0.0025 0.003 Time (sec) Signal (volts) Step Input Signal Step Input Response Figure Captions: What is the purpose of a Bode plot? What does it show? Why would you want the x axis normalized by the filter cutoff frequency? Contrast and compare the 3 different plots. Note the shape of the step input signal. Was it a true step input? What affect might the input signal spectra have on the method we used to determine the
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: transfer function? Results (cont.): Using the same technique used in labs 2 and 3 linearize the filter response to the step input function to find the value of the time constant, =RC. Using this value of RC create an Excel filter simulation of the filter you tested in the lab. Design your filter simulation so R and C are input variables. See the example spread sheet given on the class web site. You must demonstrate and explain this spreadsheet to the TA during your grading session. Show up a bit early and login to a computer in the lab and open the spreadsheet. 1. Plot the natural log of the error function, ln( (t))=ln[(y(t)-y f )/(y-y f )] vs. time. Find the time constant from the slope of the error function after the start of the step input response....
View Full Document

Ask a homework question - tutors are online