{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

homework2sol

# homework2sol - Math 4650 Homework#2 Solutions • 1.2#3ab...

This preview shows pages 1–2. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Math 4650 Homework #2 Solutions • 1.2 #3ab. Suppose p * must approximate p with relative error at most 10- 3 . Find the largest interval in which p * must lie for each value of p . Solution: The relative error is | p *- p | p = ε, so that we must have (1- ε ) p ≤ p * ≤ (1 + ε ) p . 999 p ≤ p * ≤ 1 . 001 p. 1. For p = 150 we have 149 . 85 ≤ p * ≤ 150 . 15. 2. For p = 900 we have 899 . 1 ≤ p * ≤ 900 . 9. • 1.2 #5beh. Use three-digit rounding arithmetic to perform the following calculations. Compute the absolute error and relative error with the exact value determined to at least five digits. Solution: b. 133- . 499. The exact answer to five digits is 132 . 50, which rounded to three digits is 133. e. 13 14- 6 7 2 e- 5 . 4 . The exact answer is 1 . 9535 to five digits. Using rounding arithmetic, we get 13 14 = 0 . 929 and 6 7 = 0 . 857 so that 13 14- 6 7 = . 0720. We have e = 2 . 72 so that 2 e = 5 . 44, and 2 e- 5 . 4 = 0 . 0400. Hence 13 14- 6 7 2 e- 5 . 4 = . 0720...
View Full Document

{[ snackBarMessage ]}

### Page1 / 3

homework2sol - Math 4650 Homework#2 Solutions • 1.2#3ab...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online