Quiz_1_ solution

Quiz_1_ solution - Solution to Quiz 1 April 9, 2010 1....

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Unformatted text preview: Solution to Quiz 1 April 9, 2010 1. Answer: d. Solution: (By dimension analysis, a., b. and c. can be ruled out first.) Flux : = surface E d A = a dx a dyE z = a dx a dyE y 2 b 2 = aE 1 b 2 a y 2 dy = E a 4 3 b 2 . 2. Answer: e. Solution: Denote q 1 = +20 10- 6 C, q 2 =- 10 10- 6 C, q 3 =- 4 10- 6 C. r 1 = (12 + 0 ) m, r 2 = (12 + 5 ) m, r 3 = (0 + 0 ) m. Displacement vector r 13 from q 1 to q 3 : r 13 = r 3- r 1 =- r 1 =- (12 + 0 ) m, Magnitude r 13 = (- 12) 2 + (- 0) 2 m = 12 m Unit vector r 13 from q 1 to q 3 : r 13 = r 13 r 13 =- , F 13 = k q 1 q 3 r 2 13 r 13 = ( 9 . 10 9 N m 2 /C 2 ) ( 20 10- 6 C ) (- 4 10- 6 C ) (12 m ) 2 (- ) = ( 5 10- 3 ) N Displacement vector r 23 from q 2 to q 3 : r 23 = r 3- r 2 =- r 2 =- (12 + 5 ) m, Magnitude r 23 = (- 12) 2 + (- 5) 2 m = 13 m Unit vector r 23 from q 2 to q 3 : r 23 =- ( 12 13 + 5 13 ) , 1 q 1 q 2 E 13 E 23 E x y 0.1m 0.1m 0.1m Figure 1: F 23 = k q 2 q 3 r 2 23 r 23 = ( 9 . 10 9 N m 2 /C 2 ) (- 10 10- 6 C )...
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This note was uploaded on 01/04/2011 for the course PHYS 2b taught by Professor Schuller during the Spring '08 term at UCSD.

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Quiz_1_ solution - Solution to Quiz 1 April 9, 2010 1....

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