BRAE 141 Final

BRAE 141 Final - 1. CASE 4 X 4 Tractor, 30,000 lbs, DB...

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1. CASE 4 X 4 Tractor, 30,000 lbs, DB Height = 18”, Wheel Base = 120”. a. Find the W.T. (Weight Transfer) W.T.= Pull X DB Height / Wheel Base Pull = 40% of total weight = 30,000 X .40 = 12,000 12,000 X 18 = 216,000 / 120 = 1,800 lbs = W.T. b. What is the weight of the front and rear 15,000 lbs + 1,800 lbs = 13,200 lbs on Rear 15,000 lbs – 1,800 lbs = 16,800 lbs on Front 2. John Deere 80 HPNT, 5.5 MPH Gear Speed @ 15% Slip (85% Progress), 18” DB Height, 80” Wheel Base. Soft Soil T.E. .54. a. Find Axle HPNT – Axle HPNT = Engine HPNT X T.E. on Concrete 80 / .92 (T.E. on Concrete) = 87 HP b. Find Axle HP Field – Axle HP Field = Axle HPNT X % Progress 87 / .85 (%Progress) = 74 HP c. Find DBHP Field – DBHP in Field = Axle HP X Field T.E. 74 X .54 = 40 HP d. Find Travel Speed – Travel Speed = Gear Speed X % Progress 5.5 X .85 (%Progress) = 4.7 MPH e. Find Draft/Pull – Pull = DBHP X 375 / Speed 40 x 375 = 15,000 / 4.7 = 3191 lbs = Pull f. Find Rear Weight Static on Scale (RWS). RWS = PULL / .42(Ratio Given) 3191 / .42 = 7598 lbs = RWS g. Find W.T. (weight transfer) = W.T. = Pull X DB Height / Wheel Base 3191 X 18 = 57,438 / 80 = 718 lbs. g. Find Rear Weight Under Load (RWUL) – RWUL = RWS + W.T. 7598 + 718 = 8316 lbs* = Rear Weight Under Load h. Find Total Weight of Tractor - Total = RWUL / 9 X 10 8316 / 9 = 924 X 10 = 9240 lbs = Total Weight of Tractor i. Find Front Weight Under Load (FWUL) – FWUL = Total Wt - RWUL 9240 - 8316 = 924 lbs = Front Weight Under Load
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This note was uploaded on 12/29/2010 for the course BRAE 141 taught by Professor Zetzche during the Spring '10 term at Cal Poly.

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BRAE 141 Final - 1. CASE 4 X 4 Tractor, 30,000 lbs, DB...

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