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# 4.3 pt 2 - Change Task Clear g...

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Unformatted text preview: - ._ Change Task Clear g F)K.-"I'JT=‘.-3]N{YL [nu-man: v 1 ( es of the vector field Hay} ted integral curv -Ver1ag. rt FIGURE 4.3.10. Computer-genera Math” by Hubbard and West, Springer (siny)i + (.132 - y)j (using ”Mac 1992). .15 7. F(:t:,y) = , y s. Hm) = EL, ,_.—‘” In Exercises 9412, sketch a few ﬂow lines of the given vector field, 9- Hay) = (y, ‘1‘) 10. my) = (as, w) 11. F(:c,y) = (93,552) 12. F(a:,y,z) = (y, —;c,()) 0w that the given curve C(t) is a flow line of the ‘ In Exercises 15-16, sh velocity vector field Hat, 3;, z). (62*,10g|t|,1ft),t5£ D;F{m,y,z) = (2:5, 2, -—22) 13. c[t) :2 )= (9+ 1,2,1/2z) 14- C(i) = (t2s2t — 1, JEN > 0;F(m,y.z 15. C(t) : (sint, cost,et);F(:r,y, z) z (y, -—:c,z) 16 CU) :: (\$31.84;, }£);F{\$,y12) = [‘3zd!yi——zﬁ] ...
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