hw1_sol - Homework 1 Solution 8-2 The number of observation...

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Homework 1 Solution 8-2. The number of observation n = 64 The number of intervals 8 n = = Starting point = 32.0, Ending point = 38.0 The width of each interval is (38-32)/8 = 0.75 Class Interval Frequency 32 x < 32.75 4 32.75 x < 33.5 5 33.5 x < 34.25 14 34.25 x < 35 16 35 x < 35.75 12 35.75 x < 36.5 4 36.5 x < 37.25 5 37.25 x < 38 4 37.625 36.875 36.125 35.375 34.625 33.875 33.125 32.375 15 10 5 0 C1 Frequency 4 5 4 12 16 14 5 4 8-2 Histogram Properties of the data: Shape: Unimodal (perhaps bimodal if you identify a secondary mode at ~37) Approximately Symmetric (This depends on how you define your intervals. Different selections can lead to graphs with different shape.) Location: ~34 Spread: ~6
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8-12 a) Stem-and-leaf plot N = 64 Leaf Unit = 0.10 6 32 156789 17 33 11456666688 (22) 34 0111223355666667777779 25 35 00111234456789 11 36 246888 5 37 13689 b) n = 64 1 . 2225 = x 77476 2 = x 834 . 1 63 64 ) 1 . 2225 ( 77476 2 2 = - = s s = 1.35 2225.1 34.77
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This note was uploaded on 01/04/2011 for the course ISE 31602D taught by Professor Kurtpalmer during the Fall '10 term at USC.

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hw1_sol - Homework 1 Solution 8-2 The number of observation...

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