Quiz5-Solutions

Quiz5-Solutions - Quiz 5 Solutions Part (a) At room...

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Quiz 5 Solutions Part (a) At room temperature, there are 5 modes/molecule for diatomic gas (3KE translational and 2 KE rotational , vibrational modes are frozen out) and 6 modes/molecule for solid Au/liquid Hg (3 KE and 3 PE). Part (b) 7:30am lecture: The total number of modes for each substance: 7N A *5=35N A for N 2 , 6N A *6=36N A for Hg, or, alternatively, C v =(5modes per particle)/2*(7moles)*R=145.4J/K for N 2 , and C v =(6modes per particle)/2*(6moles)*R=149.8J/K for Hg. Then the substance with the smaller total number of modes or smaller C v (N 2 ) will have greater temperature change when the same amount of heat is added to each, because Q= Δ E th =(total #modes)/2*k B * Δ T or Q= Δ E th =C v * Δ T. 9:00am lecture: The total number of modes for each substance: 5N A *5=25N A for O 2 , 3N A *6=18N A for Au, or, alternatively, C v =(5modes per particle)/2*(5moles)*R=103.9J/K for O 2 , and C v =(6modes per particle)/2*(3moles)*R=74.8J/K. Then the substance with the smaller total number of modes or smaller
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This note was uploaded on 01/05/2011 for the course PHY 7A taught by Professor Pardini during the Winter '08 term at UC Davis.

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