Quiz5-Solutions

Quiz5-Solutions - Quiz 5 Solutions Part(a At room...

Info icon This preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Quiz 5 Solutions Part (a) At room temperature, there are 5 modes/molecule for diatomic gas (3KE translational and 2 KE rotational , vibrational modes are frozen out) and 6 modes/molecule for solid Au/liquid Hg (3 KE and 3 PE). Part (b) 7:30am lecture: The total number of modes for each substance: 7N A *5=35N A for N 2 , 6N A *6=36N A for Hg, or, alternatively, C v =(5modes per particle)/2*(7moles)*R=145.4J/K for N 2 , and C v =(6modes per particle)/2*(6moles)*R=149.8J/K for Hg. Then the substance with the smaller total number of modes or smaller C v (N 2 ) will have greater temperature change when the same amount of heat is added to each, because Q= Δ E th =(total #modes)/2*k B * Δ T or Q= Δ E th =C v * Δ T. 9:00am lecture: The total number of modes for each substance: 5N A *5=25N A for O 2 , 3N A *6=18N A for Au, or, alternatively, C v =(5modes per particle)/2*(5moles)*R=103.9J/K for O 2 , and C v =(6modes per particle)/2*(3moles)*R=74.8J/K. Then the substance with the smaller total number of modes or smaller C v
Image of page 1
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern