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Unformatted text preview: What about just after? Explain briefly. b. (2.5 pts) Draw a complete momentum chart (with actual numbers in the cells) of the situation before and after the collision. From it, determine the impulse the other student imparts to you ? momentum: p = m v impulse = change in momentum 2 Solution: a. Your total momentum is (60 kg)(3 m/s) = 180 kg-m/s. That of the other cyclist is 360 kg-m/s, but in the opposite direction. Thus the total momentum is 180 kg-m/s, in the direction of the other cyclist. b. We can write the momentum chart as follows: initial change fnal you other cyclist total 180 kg-m/s-240 kg-m/s-60 kg-m/s-360 kg-m/s +240 kg-m/s-120 kg-m/s-180 kg-m/s-180 kg-m/s Thus the impulse of the other student on you is -240 kg-m/s (that is, in the direction opposite your initial motion)....
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This note was uploaded on 01/05/2011 for the course PHY 7B PHY7B taught by Professor Cebra during the Spring '10 term at UC Davis.
- Spring '10