This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: What about just after? Explain briefly. b. (2.5 pts) Draw a complete momentum chart (with actual numbers in the cells) of the situation before and after the collision. From it, determine the impulse the other student imparts to you ? momentum: p = m v impulse = change in momentum 2 Solution: a. Your total momentum is (60 kg)(3 m/s) = 180 kgm/s. That of the other cyclist is 360 kgm/s, but in the opposite direction. Thus the total momentum is 180 kgm/s, in the direction of the other cyclist. b. We can write the momentum chart as follows: initial change fnal you other cyclist total 180 kgm/s240 kgm/s60 kgm/s360 kgm/s +240 kgm/s120 kgm/s180 kgm/s180 kgm/s Thus the impulse of the other student on you is 240 kgm/s (that is, in the direction opposite your initial motion)....
View
Full
Document
This note was uploaded on 01/05/2011 for the course PHY 7B PHY7B taught by Professor Cebra during the Spring '10 term at UC Davis.
 Spring '10
 Cebra

Click to edit the document details