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hw3-sol - (400 2 7 5m 4m 11 10A LUZ WILIJ L| 3 6612(40912...

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Unformatted text preview: (400* 2% 7 5m; 4m 11 10A ' . LUZ; WILIJ+L|+3+ 6612: (40912 \/ gjz: KENS) +5 +54% (.0qu / \laJL (lung 4 5612 = (.Obfl,\/ anl \[5 Joey}? [prafil' (1meJr-ggrfl-fpz; 33¢; th‘flqfll‘efl‘ “UL: (LOWSqflSwHM: ”3.481; / 8.05 (0001612 r23 "8 :- 735/ “011» (GObwsWMHO: 15.77% W (lawn \$+(WL. 3/1‘1 I DESITEI) 1 COMPUW}; M = 5 1 = -' Q : '1'0 Way—ma Um 36V 1 \f, ‘iV', R, '{ m 9“ f fzccbé :02 :1: n= 4v, 2; =52 ,u r 13' g Nah: «I'M HM Mira WW8 to aging.“ A doling: MM hem W M0524) 'aevcn 73m. laaf'lalflcr memfs, n w mam a baflauo m [we-Mun W W mm. Inducimlg. W MW. ”it! Hi fismi bath/us 15 mk-MA 174 WWW a. WWW #5 5mm bufimms M 1mm. AS H 3‘5 :M'oo‘zSakfi TV etch-DH HM icsafeé‘ WI : 5Lv‘ 3,13 COMLInfi/f‘nrM d til/““0! 1’1/ lymuuu, wimlak ha wkwwwi expauryva/fm, M: Mazda. firm +11 dam; 1m Jmnkk 9&wa m’,7}u) L1’ x QV 37:»chn'fis ar at," L} \/ Lat-1mm [lamina W LI x w WWW M 231 " H’I‘i : {6 fl 7’ 1012, aka, 0M +L‘{ 34M Emmet} “AA 17‘ ‘i" bat-{imids )‘WJVC K41): 2"“? : LL§S1 Slag Aidlflwfitfifi) q ‘ '1‘] bflgbuei $393255 ‘1 MQ‘a‘e 34 [530 I tall/“L!" .( jec; Hahn acheur'o-H; {aw} wM-B‘ha’i‘rwt} a? Q U, Film/1(6) Mu Mfg/“Mum may, distal/l (‘5 ‘T ‘H/ Lqu-‘cs m sen-u // “ma-Ill ; w u n . I 30- 20 KO Va (L L + ”‘1st 5'0 (5 a -VB .‘l3 ,0 t1 3..) Anstg'S UPr'T San-4 1.9% H (aunrl.,, w, )(JCClpll ~/ b) finiwé'o 'va f $7.] L3); -U:'a+.-a all) 7_'::- MC) $0533 ~.(>%S \ 7. [I o LIN? t ,033 - 07533 a _ W 77 13"“??ng 7 V H77V\ “Mi __....-———— C) \‘x ' VA ”V37 ”ma” 3 - \I v M77 I 5A f 1‘ LO 3 ET ”I 3 003wfi-3 {Unsung} '1 Huge (\Oc‘ Y) 11—1H“AS?O V34“; \Ig—Vc ~V£2 10 R‘ RX“, 23 — —( \ f" L N v -- '— \ (”id (x “’2 3““ * I21 C ’ (“3% ‘1on C‘ ‘3’”!!"(130 Vi -5 VE'VC - Vii) ’ 0 R7. ifxx K“ 1 z ' L“.00‘l 002 EJ’C X L“ “3 ‘1 v5 2 av ’1 - ,, 2‘6\/ W1“? e Va: 10V VX‘ V6 Vcag O (“77" 1"“) fl 9 0 L [I ‘7",(3 IX 1 [a J' ‘3 ’ . Vé-V V -\/ {5‘5 Lil) 2 H «.3 + 5&2 L 768?» + 250 1,19%“ 3.12 The top, middle node is node A. The voltage at node A is denoted m. The KCL equation at node A is as follows: 1 1 vs ' 1; _ is . (R1+R2'Rg+Ri+Rs) A +Rl+R2 We have that em = 37.5 V. Hence, 1),; — 1)., = = 25 Cl 25 R1 __ R2 mA, an 1mm ‘01 = = 13.75 V Rs -- R4 + Rs The power dissipated, which equals the power generated is P 227515; = 3.75 W. ...
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