HW1_solution - 2 2 * 4 in a A = Load on each weld, = P/2 =...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
CE 231 Fall 2004 HW#1 (collected 9/03/04) Solution (Problem 1-39) B 500 500 500 150 150 200 C Stress developed at B = kPa m N A P 7 . 150 ) 065 . 0 ( 4 500 2 2 = = π Stress developed at D = kPa m N A P 5 . 25 ) 1 . 0 ( 4 200 2 2 = = Stress developed at C = kPa m N A P 5 . 32 ) 4 . 1 ( 4 500 2 2 = = 200 200 D 150.7 kPa 32.5 kPa 25.5 kPa
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Solution (Problem 1-81) Area of the shaded cross section,
Background image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 2 2 * 4 in a A = Load on each weld, = P/2 = 10 kip Stress on the cross section, = ksi a 2 * 4 10 At failure, maximum stress = allowable stress ksi ksi a 14 2 * 4 10 = 2 1 * 4 * 14 10 = a = 0.2525 inch a a 2 a...
View Full Document

This note was uploaded on 01/06/2011 for the course CE 231 taught by Professor Jasonweiss during the Spring '08 term at Purdue University-West Lafayette.

Page1 / 2

HW1_solution - 2 2 * 4 in a A = Load on each weld, = P/2 =...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online