CE231_Homework2 Answer - Nor mal stress along section a-a =...

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CE 231 Fall 2004 HW #2 (collected 9/08/04) Solution F 60 o F N F H a a 30 o Let A aa be the surface area along the section a-a Then A aa = 30 cos A = 2 5 . 5773 30 cos 100 * 50 mm = F= 600 N Normal force F N on the section a-a = F sin 60 = 600*sin 60 = 519.6 N
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Unformatted text preview: Nor mal stress along section a-a = kPa mm N . 90 / 09 . 50 . 5773 615 . 519 2 = = Shear stress along section a-a = kPa mm N F H . 52 / 052 . 50 . 5773 60 cos * 600 50 . 5773 2 = = =...
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This note was uploaded on 01/06/2011 for the course CE 231 taught by Professor Jasonweiss during the Spring '08 term at Purdue University-West Lafayette.

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