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# HW_3 - Solutions for Homework#3 9 a Possible values of X...

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Solutions for Homework #3 9. a. Possible values of X are positive even integers, that is {2,4,6,8,…}. X is discrete. b. Possible values are {2,3,4,5,…}. X is discrete. 10. a. {0,1,2,…,10} b. {0,1,2,3,4,5,6} c. {0,1,2,3,4,5,6} d. {0,1,2} 13. a. .10+.15+.20+.25=.7 b. .10+.15+.20=.45 c. .25 +.20+ .06+ .04=.55 d. .20 +.25 +.20+ .06=.71 e. 2 6 4 2 4 X X - . .20 +.25+ .20=.65 f. 6 4 2 X X - . .10 +.15+ .20=.45 22. a. P(X=2)=.39-.19=.20 b. P(X>3)=1-P(X 3)=1-.67=.33 c. ( 2 5) (5) ( 2 ) . 97 . 19 . 78 P X F F = - - = - = d. ( 2 5) (5 ) ( 2) . 92 . 39 . 53 P X F F < < = - - = - = 32. a. 2 ( ) ( ) E X E X p = = b. 2 2 2 ( ) ( ) { ( ) } (1 ) V X E X E X p p p p pq = - = - = - = c. 79 ( ) ( ) E X E X p = = 43. a. k=2; 1/4 b. 2. 64, 1. 54 μ σ = = ( | 2. 64 | 2(1. 54) ) 0. 25 P X - ( 0. 44 or X 5. 72) ( 6) 0. 04 P X P X ≤ - = = = Since the probability 0.04 is less than or equal to 0.25, Chebyshev’s inequality is correct, but 0.04 is too small when compared to 0.25. Thus the upper bound

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HW_3 - Solutions for Homework#3 9 a Possible values of X...

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