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3.8
System
=
contents of tank at any time
mass balance:
MM M
21
−=
∆
energy balance:
MU
MU
MH
±±
ch
∆
in
±
(a) Tank is initially evacuated
⇒
=
M
1
0
Thus
M
, and
M
2
=∆
±± ±
.
UHH
2
5
3209 6
==
°
()
=
in
bar, 370 C
kJ kg (by interpolation).
Then
?.
UU
P
T
2
53
2
0
9
6
=
=
bar,
kJ kg .
By interpolation, using the Steam Tables (Appendix
A.III)
T
=°
548 C
±
.
VP
T
°
≅
5
548
0756
C
m
kg
3
Therefore
MV
V
=
±
..
1
13228 kg
mm
k
g
33
.
(b) Tank
is
initially
filled
with
steam
at
1
bar
and
150
°
C
⇒=
=
= °
=
.
VV
P
T
1
1
150
194
bar,
C
m
kg
3
and
±
U
1
2583
=
kJ kg ,
V V
1
1
05155
===
.
k
g
M
.
Thus,
M
2
05155
=
+
.
∆
kg .
Energy
balance

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