3.8 - 3 3.8 System = contents of tank at any time mass...

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3.8 System = contents of tank at any time mass balance: MM M 21 −= energy balance: MU MU MH ±± ch in ± (a) Tank is initially evacuated = M 1 0 Thus M , and M 2 =∆ ±± ± . UHH 2 5 3209 6 == ° () = in bar, 370 C kJ kg (by interpolation). Then ?. UU P T 2 53 2 0 9 6 = = bar, kJ kg . By interpolation, using the Steam Tables (Appendix A.III) T 548 C ± . VP T ° 5 548 0756 C m kg 3 Therefore MV V = ± .. 1 13228 kg mm k g 33 . (b) Tank is initially filled with steam at 1 bar and 150 ° C ⇒= = = ° = . VV P T 1 1 150 194 bar, C m kg 3 and ± U 1 2583 = kJ kg , V V 1 1 05155 === . k g M . Thus, M 2 05155 = + . kg . Energy balance
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