4.17 - 4 4.17 Ti = 300 K, Tf = 800 K, and P = 1.0 bar i CP...

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4.17 TT P if i = 300 K, = 800 K, and = 1.0 bar CT T T T P -2 -5 2 -9 3 ( ) = 29.088 - 0.192 10 + 0.4 10 - 0.870 10 J mol K ×× × T dT P dP P P WC T d T T T P P f rev T T i f i f i f P K K 6 P K K Calculated final pressure
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This note was uploaded on 01/06/2011 for the course CHE 330 at USC.

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