EEL3472HA5S - H4-eF*t( 2ol0pro5lcm 6..l A stationary...

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Unformatted text preview: H4-eF*t( 2ol0pro5lcm 6..l A stationary conducting loop with an internal resistance of 0.5 Cl isplaced in a time-varying magnetic field. When the loop is closed, a current of 5 Ahows through it. What will the current be if the loop is opened to create a small gapand a 2-O resistor is connected across its open ends?Solution: %.r is independent of the resistance which is in the loop. Therefore, whenthe loop is intact and the internal resistance is only 0.5 O,Vemf :5 A x 0.5 Cl : 2.5 V..When the small gap is created, the total resistance in the loop is infinite and thecurrent flow is zero. With a 2-C) resistor in the gap,I : Y"nl (2 Cl + 0.5 0) -- 2.5 v 12.5 C) : I (A)'v c m r - - - # : l ' 1 x Z n x l 0 a s i n ( 2 z r x l 0 a r ) x l 0 - 7: 6.9 x l0-3 sin(22 x l0at) (V).( b ), V c m f 6 , 9 x l 0 - i _ : _ / . - . . r n 4 . \ _ 1 a o ^ : ^ t . t * . , Irind:4-JJ : # sin(2nx lgar) : l.38sin(2nxl1at) (mA).At t :0, B is a maximum, it points in -i-directibn, and since it varies ascos(2n x lOat), it is decreasing. Hence, the induced current has to be ;: CW whenlooking down on the loop, as shown in the figure.pr0blenr 6.6 The square loop shown in Fig. P6.6 is coplanar with a long, straightwire carrying a current1(l) : 5cos(2zr x lOar) (A)'(a)Determinetheemfinducedacrossasmallgapcreatedintheloop.(b) Determine the direction and magnitude of the current that would flow througha 4-Q resistor connected across the gap. The loop has an intemal resistance oflo.f igure P6.6: Loop coplanar with long wire (Problem 6'6)'Solution:(a) The magnetic field due to the wire is^ ltol ^ 1t4lB : Q T * : - * z n y ,where in the plane of the loop, 0 : -i and r : l.The flux passing through the loopiso: IB.ds : Srs cn (-* 9) ' [-* lo (cm)] dv- Js- "/s "' \ ztcY /u o l x l 0 - 1 . 1 5: ' - l n -2 n 5...
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This note was uploaded on 01/06/2011 for the course EEL 3472 taught by Professor Rakov during the Spring '08 term at University of Florida.

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EEL3472HA5S - H4-eF*t( 2ol0pro5lcm 6..l A stationary...

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