{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

EEL3472HA6S

# EEL3472HA6S - Ht t F*A zo(o Proltlem7.2 Write general...

This preview shows pages 1–4. Sign up to view the full content.

Ht? t F*A zo(o Proltlem 7.2 Write general expressions for the electric and magnetic fields of a l-GHz sinusoidal plane wave traveling in the *y-direction in a lossless nonmagnetic medium with relative permittiviV e, :9. The electric field is polarized along the -r-direction, itspeakvalue is 6Ylm, and itsintensityis4 v/m att:0and,y:)sr'r.. Soltttion: For f - I GHz, Fr: l, and r, : 9, ro :2nf :2tr x 109 rad/s, . 2n 2rc 2nf 2n x l}e r:T: An{q: " {4:J;lo8 t/9:2onradlm, E(y,t) : i6cos(2zr x l0er -20ny+ Qd ff/m). At t : 0 andy : 2 cm, E : 4Ylm: 4 : 6cos(-Z\n x2x t0-2 + fu) : 6cos(-0.42+ O0). Hence, to-0.4n: cos-r (;) : o.84rad, which gives and h:2.1rad: l20.l9o E(y,t): i 6cos(2zr x l0el -20ny* 120.19') (V/m).

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Problem T.4 The electric field of a planewave propagating in a nonmagnetic material is given by n: [y3sin(zr x l01t -0.2nx) * il4cos(n x 107 t - 0.2nx)l (V/m) Determine (a) The wavelength. (b) s.. (c) H. Solution: (a) Since k:0.2n, , _2o - rL:ro^. n: -F: T2n (b) 0) nxlo. - .^1 ur:T:-oU;:)Xlu'rvS' uP: G' Hence, - _ ( " \'_ /3 "_lol\'= ro. o:\a/:\5"r0'7 (c) H: +R x E: l* * [irrtn (tt x l07t -0.2nx) *L4cos(n x l07t -o'acx)] nq : 21 sin(n x 107 t - 0.2nx)- 91.os(r x l07t - 0.2nx) (A/m), ' 'n with rh l2on n: ft= T:20n:62.83 (O).
Problern 7.6 The electric field of a plane wave propagating in a lossless, nonmagnetic, dielectric material with q :2.56 is given by P : \$'20cos (6n x l}et - kz) (V/m) Determine: (a) .f , uo, h, k, and 4.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern