{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

EEL3472HA6S - Ht t F*A zo(o Proltlem7.2 Write general...

Info icon This preview shows pages 1–4. Sign up to view the full content.

View Full Document Right Arrow Icon
Ht? t F*A zo(o Proltlem 7.2 Write general expressions for the electric and magnetic fields of a l-GHz sinusoidal plane wave traveling in the *y-direction in a lossless nonmagnetic medium with relative permittiviV e, :9. The electric field is polarized along the -r-direction, itspeakvalue is 6Ylm, and itsintensityis4 v/m att:0and,y:)sr'r.. Soltttion: For f - I GHz, Fr: l, and r, : 9, ro :2nf :2tr x 109 rad/s, . 2n 2rc 2nf 2n x l}e r:T: An{q: " {4:J;lo8 t/9:2onradlm, E(y,t) : i6cos(2zr x l0er -20ny+ Qd ff/m). At t : 0 andy : 2 cm, E : 4Ylm: 4 : 6cos(-Z\n x2x t0-2 + fu) : 6cos(-0.42+ O0). Hence, to-0.4n: cos-r (;) : o.84rad, which gives and h:2.1rad: l20.l9o E(y,t): i 6cos(2zr x l0el -20ny* 120.19') (V/m).
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Problem T.4 The electric field of a planewave propagating in a nonmagnetic material is given by n: [y3sin(zr x l01t -0.2nx) * il4cos(n x 107 t - 0.2nx)l (V/m) Determine (a) The wavelength. (b) s.. (c) H. Solution: (a) Since k:0.2n, , _2o - rL:ro^. n: -F: T2n (b) 0) nxlo. - .^1 ur:T:-oU;:)Xlu'rvS' uP: G' Hence, - _ ( " \'_ /3 "_lol\'= ro. o:\a/:\5"r0'7 (c) H: +R x E: l* * [irrtn (tt x l07t -0.2nx) *L4cos(n x l07t -o'acx)] nq : 21 sin(n x 107 t - 0.2nx)- 91.os(r x l07t - 0.2nx) (A/m), ' 'n with rh l2on n: ft= T:20n:62.83 (O).
Image of page 2
Problern 7.6 The electric field of a plane wave propagating in a lossless, nonmagnetic, dielectric material with q :2.56 is given by P : $'20cos (6n x l}et - kz) (V/m) Determine: (a) .f , uo, h, k, and 4.
Image of page 3

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 4
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern