Heimadaemi_06_lausnir

Heimadaemi_06_lausnir - A F5GF ja Ö×k iÔ ØaÚ e Ök...

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Unformatted text preview: A F5GF ja Ö×k iÔ ØaÚ e Ök fÖð i e iÑ adÑ i6aÙ ×Ò iÖ Ñ × jóÒa ÖkeÒÒa Ö i:Öe fÒaa Ö íÒG ÙÒÒa Ö×dó ØØ iÖ k iÐi×Øíhó Ðf9 fÝ Ö iÖk Ð8 :Ñ iðÚ ikÙdag iÒÒÓk Øób e Ö DÑ i F iÒÒ iðÝÕÙ i×Ø×ö fÒÙÒa ÖØ íðÒ ie fØ iÖ fa ÖaÒd iÑ eÖk ja a m 1 ( t ) ×eÑ h e fÙ ÖØ íðÒ iþ ØØ iÑ iÐÐikÞÓg8kÞ b m 2 ( t ) = sin(2 πf m t ) cos(2 √ 5 πf m t ) c m 3 ( t ) = m 2 ( t ) + cos(2 πf m t ) sin(2 √ 5 πf m t ) d m 4 ( t ) = sin 3 (2 πf m t ) e m 5 ( t ) = ÖecØ ( at ) aÙ ×Ò : ÝÕÙ i×Ø×ö fÒÙÒa ÖØ íðÒ iÒ f s eÖØÚ i×Úa Ö× iÒÒÙÑ h ÖÖ ieÒh ×Ø iØ íðÒ iþ ØØÙ ÖÑ eÖk i× W FÙÑ a f s 1 = 2(8 kÞ ) = 16 kÞ b úg iÐd iÖað sin α cos β = 1 2 [sin( α- β ) + sin( α + β )] FÙÑ þÚ í m 2 ( t ) = sin(2 πf m t ) cos(2 √ 5 πf m t ) = 1 2 [sin(2 π (1- √ 5) f m t ) + sin(2 π (1 + √ 5) f m t )] eÖ W = (1 + √ 5) f m Óg f s 2 = 2 W = 2(1 + √ 5) f m c eÑ fÝ ÖÖg iÐd iÖað sin α cos β = 1 2 [sin( α- β ) + sin( α + β )] eÖ W = (1 + √ 5) f m e iÒ × Óg fÝ Ö iÖ m 2 ( t ) Ógþa ÖÑ eð f s 3 = 2(1 + √ 5) f m d e ikÒÙÑ m 4 ( t ) = sin 3 (2 πf m t ) = sin 2 (2 πf m t ) sin(2 πf m t ) = 1 2 [1- cos(4 πf m t )] sin(2 πf m t ) = 1 2 sin(2 πf m t )- 1 4 [- sin(2 πf m t ) + sin(2 π (3 f m ) t )] = 3 4 sin(2 πf m t )- 1 4 sin(2 π (3 f m ) t ) ö fÙÑ þa ÖÑ eðað W = 3 f m ×ÚÓ f s 4 = 6 f m e F ÓÙ Ö ieÖÚö ÖÔÙÒ m 5 ( t ) = ÖecØ ( at ) eÖ M 5 ( f ) = 1 | a | × iÒ c ( f a ) iÒ c fa ÐÐiðeÖóeÒdaÒ Ðeg Ø íØ íðÒ i þaðeÖþaðh e fÙ ÖóeÒdaÒ ÐegabaÒdÚ íddG...
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Heimadaemi_06_lausnir - A F5GF ja Ö×k iÔ ØaÚ e Ök...

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