final08_solution

# final08_solution - Suggested Solution Question 1: (a) mean...

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5 Suggested Solution Question 1: (a) mean = 000 , 50 10000 5 = × ; standard deviation = 89443 40000 5 = × (b) 17889 5 / 40000 = (c) 282843 40000 50 ; 000 , 500 10000 50 50 50 = × = = × = σ μ , -500,000/282843 = -1.77 0394 . 0 ) 77 . 1 ( = < Z P , By central limit theorem, we don’t need to make any assumption on the distribution of X. (e) Since this is a small sample problem, we assume that X has normal distribution. In this Case 126491 40000 10 ; 000 , 100 10000 10 10 10 = × = = × = ; (-40000 – 100000)/126491=-1.11, 1335 . 0 ) 11 . 1 ( = < Z P Question 2: (a) B A p p H = > = : reject 96 . 1 282 . 2 1000 / 2 * ) 96 . 0 ( 04 . 0 03 . 0 05 . 0 0 . (b) %] 715 . 3 %, 285 . 0 [ 1000 / %) 95 % 5 % 97 % 3 ( 96 . 1 %) 3 % 5 ( = × + × ± (c) 62 . 2 2000 / % 97 % 3 / %) 3 % 4 ( = × p-value =0.44% (d) 0 2 2 reject 33 . 2 974 . 3 50 / 30 30 / 50 / ) 165 205 ( H > = + (c) The two populations of order sizes for Catalogues A and B are both normal with equal variance. Question 3:
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## This note was uploaded on 01/06/2011 for the course BBA ISOM111 taught by Professor Hu during the Fall '08 term at HKUST.

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