Tutorial Solutions 1C

# Tutorial Solutions 1C - EE2006 Digital Design 15 Z = A B B...

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EE2006: Digital Design 1 15. D B B A C B D B D C B B A Z + + = + + = Logic circuit 16. MSOP ABD ABC BCD ACD Z + + + = MPOS (A C) (B D) (A D) (B D) (C B) (A Z + + + + + + = H . A C.H H . B D.H H . C B H . B A H . D B H . D B B A C B + + H . B H . A H . B H . D B B A C B Z + + = 0 00 01 11 10 AB CD 0 0 0 0 1 0 0 0 0 1 0 0 1 1 1 00 01 11 10 0 00 01 11 10 AB CD 0 0 0 0 1 0 0 0 0 1 0 0 1 1 1 00 01 11 10 0 00 01 11 10 AB CD 1 1 1 1 0 1 1 1 1 0 1 0 1 0 0 00 01 11 10

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EE2006: Digital Design 2 (a) C) (A C) (B D) (A D) (B D) (C B) (A Z + + + + + + = (b) ABD ABC BCD ACD Z + + + = CD Α Η C A.H B.H D .H Z.H = ACD + BCD + ABC + ABD.H ACD + BCD + ABC .H Z .H CD B ABC ABD A.H B.H C.H A .H D .H B A + .H D C + .H D B + .H D A + .H C B + .H C A + .H D) (B D) (C B) (A + + + .H C) (A C) (B D) (A + + + .H Z.H Z.H B .H Η D Η C
EE2006: Digital Design 3 17. We are required to find the magnitude, M , of a 4-bit number, N , expressed in 2’s complement notation. In a circuit implementation, the magnitude of a 2’s complement is found by inverting all the bits of a number and adding 1 to it if the number is negative. We can equivalently write M = N if N is positive. Else M = complement( N ) + 1 if N is negative.

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## This note was uploaded on 01/08/2011 for the course EE 2006 taught by Professor Dr. during the Spring '10 term at National University of Singapore.

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Tutorial Solutions 1C - EE2006 Digital Design 15 Z = A B B...

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