WI08Ma2bHw4Sol

WI08Ma2bHw4Sol - Math 2b Winter 2009 Solutions to Homework 4 1 A new elevator in a large hotel is designed to carry about 30 people with a total

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Math 2b, Winter 2009: Solutions to Homework 4 1. A new elevator in a large hotel is designed to carry about 30 people, with a total weight of up to 5000 lbs. More than 5000 lbs. overloads the elevator. The average weight of guests at this hotel is 150 lbs., with an SD of 55 lbs. Suppose 30 of the hotel’s guests get into the elevator. Assuming the weights of these guests are independent random variables, what is the chance of overloading the elevator? Give your approximate answer as a decimal. Solution. Let X 1 ,...,X 30 be random variables representing the weights of the 30 guests who get into the elevator, and let S = 30 i =1 X i . The X i ’s are identically distributed independent random variables with mean 150 and standard deviation 55, which means S is a random variable with mean 150 · 30 = 4500 and standard deviation 55 30. There are enough people in the elevator to use the Central Limit Theorem to say that S is approximately normally distributed. Thus the probability of overloading the elevator is approximately the probability of being at least 5000 - 4500 55 30 1 . 660 standard deviations above the mean in a normal distribution. This is given by 1 - Φ(1 . 660) 0 . 048, so there is roughly a 5% chance of overloading the elevator. 2. Suppose X and Y are independent random variables such that EX 4 = 2, 2 = 1, EY 2 = 1, and = 0. Let W = X 2 Y . Calculate EW , 2 , SD ( W ).
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This note was uploaded on 01/08/2011 for the course MA 2b taught by Professor Makarov,n during the Winter '08 term at Caltech.

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WI08Ma2bHw4Sol - Math 2b Winter 2009 Solutions to Homework 4 1 A new elevator in a large hotel is designed to carry about 30 people with a total

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