October 1 Solutions

# October 1 Solutions - 6.3 IDENTIFY Each force can be used...

This preview shows pages 1–2. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 6.3. IDENTIFY: Each force can be used in the relation ( cos ) W F s F s for parts (b) through (d). For part (e), apply the net work relation as net worker grav . n f W W W W W SET UP: In order to move the crate at constant velocity, the worker must apply a force that equals the force of friction, worker k k . F f n EXECUTE: (a) The magnitude of the force the worker must apply is: 2 worker k k k 0.25 30.0 kg 9.80 m/s 74 N F f n mg (b) Since the force applied by the worker is horizontal and in the direction of the displacement, and the work is: worker worker cos 74 N cos0 4.5 m 333 J W F s (c) Friction acts in the direction opposite of motion, thus 180 and the work of friction is: k cos 74 N cos180 4.5 m 333 J f W f s (d) Both gravity and the normal force act perpendicular to the direction of displacement. Thus, neither force does Both gravity and the normal force act perpendicular to the direction of displacement....
View Full Document

{[ snackBarMessage ]}

### Page1 / 2

October 1 Solutions - 6.3 IDENTIFY Each force can be used...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online