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Homework 4 Solutions

# Homework 4 Solutions - Engineering Math ﬂamework 4...

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Unformatted text preview: Engineering Math ﬂamework 4 Seiutions Spﬁﬂg 201i} (1) A 2 (4,0,9), 3 2 (1,0,6), 0 = (0,2133), D 2 (1, 5, m4) ‘ *4 -+ m) l w) -+ i3 1 k E (a) A X A Q 5 [~24, ~24, “£12; 4 0 f ~24{\$ w 4) _ 24;; ~ 122 = 0 443: w My — 122: m —~—96 23:4—2312228 (b) 2(1)+2{5)+(—4) 28 ~/ ((2) Separate the ﬁgure into two triangies, say, ABC and ACE. The area of each triangle 13 haif the area of the paraﬂeiogram determined by the same vectors a area oftriangle ABC = \$1,479 >< AC 1 : §][~24,m24,_12§l :2 i M576 + 576 + 144 = i(3&218 2 2 -.+ a ~+ —-o w) y 1 .3 k F A X A 2 é..4 4 0 2 s,«-16,-16,—8] A, {—3 5 m4 area oftriangle A013: 5-; AC >< ADi— %‘[—16,-16,—8][ éx/256 + 256 + 64 m 5424) m 12 area 0fquadriiateral:18 4.. 12 2 30 II (2) "gm 2 [e‘cos t, etsint, at} t 2 G to t 2 1 *V t « , é 2: , t - 25 r (t) 2 [~28 smt ~1— e caste cost—r 8 \$313th } fiﬂ}! 2 M~etsint + etcost, etcost + egsiﬂt, 6‘] I 2 Vf’gegtsingt w» 23233th cost ~§« eZ‘cos-Qt + agims’gé + 2873th t 3th + egtsingt + 821 2 V eggsingt + excaszi + BZtCOSZt + 82153332}? + 633 M V432: _§, eat ,3, 82:31" V1362: ... ﬁe: E2 Jyﬁe‘dt 2 V’Eéltj: 2 ﬁﬁa ~1) ...
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