sol6-1 - Problem Set 6 Calculus 1 Abdullah Khalid, Hassan...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Problem Set 6 Calculus 1 Abdullah Khalid, Hassan Bukhari December 31, 2010 1. We have v ( t ) = 0 . 001302 t- . 09029 t 2 + 23 . 61 t 3- 3 . 083. We find the acceleration by differentiating this w.r.t. t . a ( t ) = v ( t ) = 0 . 001302- 2 × . 09029 t + 3 × 23 . 61 t 2 = 0 . 001302- . 18058 t + 70 . 83 t 2 To find maximum velocity, we find all critical points, by differentiating the above expres- sion again and putting it equal to zero a ( t ) = 0- . 18058 + 141 . 66 t = 0 Which gives us t = 0 . 001275 Hence we have a (0 . 001275) = 0 . 001187 Now we evaluate the a(t) at the endpoints, t = 0 and t = 126. a (0) = 0 . 001302 a (126) = 1124474 So, the maximum acceleration is just before the fuel runs out at t = 126 and is equal to 1124474. 2. For f ( x ) = 1- x 2 / 3 , we compute the derivative, which comes out to be f ( x ) = 1- 2 3 x 1 / 3 . This is undefined for x = 0. Rolle’s theorem requires that the function have a derivative at every point in the given domain. Since, this condition is not true, Rolle’s theorem does not apply to this situation....
View Full Document

Page1 / 3

sol6-1 - Problem Set 6 Calculus 1 Abdullah Khalid, Hassan...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online