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Unformatted text preview: glass, the radius from the origin, and the distance x . θ φ x R ' R sin( φ + π/ 2) = x sin φ This gives x = R sin φ sin( φ + π/ 2) = R 1 /n cos φ = R 1 /n q 1sin 2 θ/n 2 = R p n 2sin 2 θ . A similar construction on the other side (negative x ) gives R sin(φ + π/ 2) =x sin φ This givesx = R sin φ sin(φ + π/ 2) = R 1 /n cos φ = R 1 /n q 1sin 2 θ/n 2 = R p n 2sin 2 θ , so that the result is symmetric on the two sides of the centerline. This region can extend to the full distance where x = ± R if the denominator is one: p n 2sin 2 θ = 1 , or sin 2 θ = n 21 . The sine can never be larger than one, so this can happen only if n 2 < 2, or n < √ 2....
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 Spring '10
 RazaSuleman

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