pointer_arithmetic

pointer_arithmetic - printf"%hd\n"(p 3 Output...

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Pointer arithmetic exercise Consider the following program. Write the output after each printf statement inside the accompanying comment. You don’t need to write newline characters. sizeof(short) is 2, and the memory address of a[0] is 0xbf9eb8c6 . The address increases from a[0] to a[4] . The conversion specification %p is for printing address in hexadecimal form. The conversion specification %hd is for printing a short variable. /* pointer arithmetic */ #include <stdio.h> int main() { short *p; short a[] = {0, 1, 2, 3, 4}; short *pa[] = {a+4, a+3, a+2, a+1, a}; printf("%p\n", &a[0]); /* Output: 0xbf9eb8c6 */ printf("%p\n", &a[1]); /* Output: ___________ */ printf("\n"); printf("%d\n", a - &a[0]); /* Output: ___ */ printf("%p\n", a + 2); /* Output: ___________ */ printf("%hd\n", *(a + 4)); /* Output: ___ */ printf("\n"); p = a; printf("%p\n", ++p); /* Output: ___________ */ printf("%hd\n", p[0]); /* Output: ___ */
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Unformatted text preview: printf("%hd\n", *(p + 3)); /* Output: ___ */ printf("\n"); p = &a[4]; printf("%hd\n", *(p - 4)); /* Output: ___ */ printf("%hd\n", p[-1]); /* Output: ___ */ 1 printf("\n"); p = a + 2; printf("%hd\n", *p++); /* Output: ___ */ printf("%hd\n", *--p); /* Output: ___ */ printf("\n"); p = a + *(a + 3); printf("%d\n", a - p); /* Output: ___ */ printf("%d\n", a == &p[-3]); /* Output: ___ */ printf("\n"); p = pa[3]; printf("%hd\n", a[p - a]); /* Output: ___ */ printf("%hd\n", *(p + (a[4]-a[1]))); /* Output: ___ */ printf("\n"); printf("%d\n", pa[0] - a); /* Output: ___ */ printf("%hd\n", *(pa[4] + a[4])); /* Output: ___ */ printf("%d\n", (pa[2] - &a[2])); /* Output: ___ */ printf("\n"); { int i; for (i = 0; i < 5; i++) { *pa[i] = a[i]; printf("%hd ", a[i]); /* Output: ___________*/ } printf("\n"); } return 0; } 2...
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This note was uploaded on 01/10/2011 for the course CSC 180 taught by Professor Na during the Fall '01 term at University of Toronto.

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pointer_arithmetic - printf"%hd\n"(p 3 Output...

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