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Unformatted text preview: EECS 216 SOLUTIONS TO PROBLEM SET #1 Winter 2008 1a. Using voltage divider, H ( j ) = [1 / ( jC )] / [ R + jL +1 / ( jC )] = 1 / [1 2 LC + jRC ] Note: Units or dimensions: every term is dimensionless. This is a good check. 1b. Assume default units. L=1 H,C=1 F,R=0.1 H ( j ) = 1 / [(1 2 ) + j . 1]  H ( j )  = 1 / radicalbig (1 2 ) 2 + 2 / 100 and negationslash H ( j ) = tan 1 / 100 1 2 But: Add to phase if   > 1. IF you had any trouble with this, retake EECS 215! Matlab: W=linspace(0,2);subplot(421),plot(W,abs(1./(1W. 2+j*W/10))) subplot(422),plot(W,angle(1./(1W. 2+j*W/10))) if have no sig. proc. toolbox. 2a. 3 4 j = 5 e j. 927 = 5 negationslash . 927. Also: 12 + j 5 = 13 negationslash . 395 (not required). 2b. [(3 4 j ) + (12 5 j )] 2 = (15 9 j ) 2 = 225 81 2 j 15 9 = 144 270 j = 306 negationslash 1 . 081 2c....
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This note was uploaded on 04/03/2008 for the course EECS 216 taught by Professor Yagle during the Fall '08 term at University of Michigan.
 Fall '08
 Yagle
 Volt

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