Introduction to Genetic Analysis 141

Introduction to Genetic Analysis 141 - 44200_04_p115-150...

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140 Chapter 4 Eukaryote Chromosome Mapping by Recombination 1000 linear asci are isolated and categorized as in the above table. Map the ad and nic loci in relation to centromeres and to each other. Solution What principles can we draw on to solve this problem? It is a good idea to begin by doing something straightfor- ward, which is to calculate the two locus-to-centromere distances. We do not know if the ad and the nic loci are linked, but we do not need to know. The frequencies of the M II patterns for each locus give the distance from lo- cus to centromere. (We can worry about whether it is the same centromere later.) Remember that an M II pattern is any pattern that is not two blocks of four. Let’s start with the distance be- tween the nic locus and the centromere. All we have to do is add the ascus types 4, 5, 6, and 7, because they are all M II patterns for the nic locus. The total is 5 ± 90 ± 1 ± 5 ² 101 out of 1000, or 10.1 percent. In this chap- ter, we have seen that to convert this percentage into map units, we must divide by 2, which gives 5.05 m.u.
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