phantom - Pair-wise pan-pot permit permits positioning of...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Pair-wise pan-pot permit permits positioning of sound source Non-zero gain is applied only to the two speakers adjacent to the phantom image location Even if there are more than two speakers, only the pair which encloses the phantom image is considered. L θP θ2 θ1 R Assuming gain decreases linearly in one channel and increase linearly in the other, we have θ 2 ≥ θ P ≥ θ1 g1 = g2 = θ2 − θ P θ 2 − θ1 θ P − θ1 θ 2 − θ1 Total gain = ∑ g i i =1 2 Total power = ∑ gi i =1 2 2 Ideal case: independent on image position Let θ 2 = 45o ,θ1 = 315o ( −45o ) 1.2 1 0.8 0.6 0.4 0.2 0 5 Linear Panning: Total Gain Channel one Channel two Total gain Constant Gain Optimization Linear Panning: Total Power 1.2 1 0.8 0.6 0.4 0.2 0 -4 5 -3 5 -2 5 -1 5 5 15 25 35 45 -5 Loudness is proportional to power instead of gain 25 -2 5 -4 -3 -1 45 5 5 15 35 -5 5 Channel one Channel two Total Power θ − θ1 Let θ m = 90 P θ −θ 1 2 g1 = cos θ m g 2 = sin θ m Constant Power Panning: Total Gain 1.6 1.4 1.2 1 0.8 0.6 0.4 0.2 0 -0.2 Constant Power Optimization Channel one Channel two Total gain 25 35 -4 -3 -2 Constant Power Panning: Total Power 1.2 1 0.8 0.6 0.4 0.2 0 -4 5 -3 5 -2 5 -1 5 5 15 25 35 45 -5 -1 45 5 15 5 5 5 5 -5 Channel one Channel two Total Power ...
View Full Document

Page1 / 3

phantom - Pair-wise pan-pot permit permits positioning of...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online