5 pn Diode Applications - Part 1 - Solution

5 pn Diode Applications - Part 1 - Solution - (Q2 t vo(t =...

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(Q2) - = C R t v t v L m o exp ) ( , ) ( ) ( 1 0 t v t v v o o o - = Δ , m o v t v = ) ( 0 ( ) - - - = Δ C R t t v v v L m m o 0 1 exp , ( ) - - - = Δ C R t t v v L m o 0 1 exp 1 C R t t L << - 0 1 , 1 1 ) exp( << - - x for x x - - - Δ C R t t v v L m o 0 1 1 1 , - Δ C R t t v v L m o 0 1 , f t t 2 1 0 1 - f - operating frequency (original freq.) C fR v v L m o 2 Δ
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(Q3) The circuit of Figure 3 is used to rectify a sinusoid of 100V rms and 60Hz. The minimum voltage output cannot drop below 70V. The load resistance is 2k Ω . What size capacitor need across
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5 pn Diode Applications - Part 1 - Solution - (Q2 t vo(t =...

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