{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

6 pn Diode Applications - Part 2 - Solution

# 6 pn Diode Applications - Part 2 - Solution - Tutorial pn...

This preview shows pages 1–3. Sign up to view the full content.

Tutorial – pn Diode Applications – Part 2 (1) Chapter 2 Questions – 42, 43, 44 and 45. Answers :- (42) a. 9V, 50mA, 0mA, 50mA b. 10V, 21.28mA, 24.17mA, 45.45mA c. 1.8k Ω d. 220 Ω (43) a. V Z = 12V, R S = 20 Ω , R L = 60 Ω b. 2.4W (44) V i(min) = 11.31V V i(max) = 15.86V (45) R S = 0.5k Ω I ZM 40mA (2) A zener diode having a breakdown voltage of 10V at 25 o C has a temperature coefficient of +5.5mV/ o C. It is to be temperature compensated by connecting it in series with three forward-biased diodes, as shown in Figure 2. Each compensation diode has a forward drop of 0.65V at 25 o C and a temperature coefficient of –2mV/ o C. (i) What is the temperature stability of the uncompensated zener diode? (ii) What is the breakdown voltage of the uncompensated zener diode at 100 o C? (iii) What is the voltage across the compensated network at (a) 25 o C and (b) 100 o C? (iv) What is the temperature stability of the compensated network? Answers - (i) 0.055% (ii) 10.4125V (iii) 11.95V, 11.9125V (iv) 0.00418% Figure 2 V i V o

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
42. (a) Determine V L , I L , I Z and I R for the network Fig. 2.181 if R L = 180 Ω .
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 10

6 pn Diode Applications - Part 2 - Solution - Tutorial pn...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online