7 pn Diode Applications - Part 3 - Solution

7 pn Diode Applications - Part 3 - Solution - Tutorial 2...

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Tutorial 2 pn-Diode Applications – Part 3 (1) Chapter 2 Questions - 36 (assume V th = 0.7volt), 37, 47 and 48. Answers :- (47) 339.36V (48) 2.828V rms (2) Determine the output waveform of the circuits of Figure 2a (clipper) and Figure 2b (clamper). (Assuming ideal diodes, i.e. V T =0 and R F =0.) AC D 2 D 1 4V 5V 10k 5k v i 10sin(1000t)V v o Figure 2a V R C v o v i (RC >> T , V m > V ) Figure 2b v i t V m -V m T
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Solutions 36. For the positive region of v i : The right Si diode is reverse-biased. The left Si diode is “on” for levels of v i greater than 5.3 V + 0.7 V = 6 V. In fact, v o = 6 V for v i 6 V. For v i < 6 V both diodes are reverse-biased and v o = v i . For the negative region of v i : The left Si diode is reverse-biased. The right Si diode is “on” for levels of v i more negative than 7.3 V + 0.7 V = 8 V. In fact, v o = - 8 V for v i - 8 V. For v i > - 8 V both diodes are reverse-biased and v o = v i . i
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This note was uploaded on 01/11/2011 for the course EE 2106 taught by Professor Ytchow during the Spring '07 term at City University of Hong Kong.

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7 pn Diode Applications - Part 3 - Solution - Tutorial 2...

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