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Unformatted text preview: Tutorial  BJT Basic Principle  Solutions Fig. 3.10 Solution (a) r av = 0.9 V 0.7 V 8 mA V I Δ = Δ = 25 Ω (b) Yes, since 25 Ω is often negligible compared to the other resistance levels of the network. Fig. 3.8 Solution (a) I C ≅ I E = 4.5 mA (b) I C ≅ I E = 4.5 mA (c) Negligible: change cannot be detected on this set of characteristics. (d) I C ≅ I E Fig. 3.7 Fig. 3.8 Fig. 3.10 Fig. 3.7 Fig. 3.8 Solution (a) Using Fig. 3.7 first, I E ≅ 7 mA Then Fig. 3.8 results in I C ≅ 7 mA (b) Using Fig. 3.8 first, I E ≅ 5 mA Then Fig. 3.7 results in V BE ≅ 0.78 V (c) Using Fig. 3.10(b) I E = 5 mA results in V BE ≅ 0.81 V (d) Using Fig. 3.10(c) I E = 5 mA results in V BE = 0.7 V (e) Yes, the difference in levels of V BE can be ignored for most applications if voltages of several volts are present in the network. Fig. 3.10 Solution (a) I C = α I E = (0.998)(4 mA) = 3.992 mA (b) I E = I C + I B ⇒ I C = I E I B = 2.8 mA  0.02 mA = 2.78 mA α dc = 2.78 mA 2.8 mA C E I I = =...
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This note was uploaded on 01/11/2011 for the course EE 2106 taught by Professor Ytchow during the Spring '07 term at City University of Hong Kong.
 Spring '07
 YTChow

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