extra 7 - BER and SER for QPSK x t = A cos(2 f c t B sin(2...

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1 BER and SER for QPSK In the lecture notes, it has been shown that z A and z B are given by Following a similar procedure as that for BPSK, we can show that As each QPSK symbol carries two bits, we have (See textbook page 283.) 0.5 0.5 AB z A noise z B τ =+ ( ) cos(2 ) sin(2 ) cc x tA f tB f t π = + cos (2π f c t ) decision device
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