Tutorial8_ans - 1 =ct sinmt 2sin2mt EE 3008 FM Tutorial...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
EE 3008. FM Tutorial Solutions 1. θ = ω c t + sin ω m t + 2sin2 ω m t t t dt d m m m m c ω θ 2 cos 4 cos + + = Therefore ∆ω = ω m cos ω m t+4 ω m cos2 ω m t At t=0, ∆ω max = ω m +4 ω m = 5 ω m or f max =5f m = 5kHz 2.(i) β = ∆ω / ω m =100/(10 × 10 3 ) = 0.01 (NBFM), B 2f m =20kHz. (ii) NBFM, B 2f m =20kHz. (iii) NBFM, B 2f m =40kHz. (iv) NBFM, B 2f m =40kHz. 3.(i) f=4 × 1000=4kHz (ii) W 100 50 2 100 ) ( 2 2 = × = Φ = R t P t (iii) f m =1kHz, β = f/f m =4, f c =10 7 Hz=10MHz (i.e., n=0) Therefore at 10 MHz, the average power is W 16 ) 4 . 0 ( 100 ) 4 ( 2 2 0 0 = = × = J P P t (iv) Using Carson’s rule: B 2( f + f
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

Ask a homework question - tutors are online