Tutorial08 - T8-1City University of Hong Kong Electronic...

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Unformatted text preview: T8-1City University of Hong Kong Electronic Engineering Semester B 2007-2008 EE3108 Engineering Analysis Tutorial 8 A RLC resonant circuit can be solved using a second-order ordinary differential equation (ODE). We consider the following circuit with R= 20 Ω, L= 1 mH, and C= 2.53 nF. We are interested to calculate the voltage y(t). Assume that the capacitor is initially charged with y(0) = 5 V and there is no current at time t= 0 so that y'(0) = 0. -L di/dtL C1/12222=+++=−+=−yLCdtdyRLdtydydtdyRCdtydLCyiRdtdiLFrom studying the dimensions of the equation, the relevant time constants are (LC)1/2 = 1.6 µs and L/R= 50 µs. Thus, it is should be wise to choose a time step for simulation to be much less than 1.6 µs. Furthermore, the second-order equation can be rewritten as two first-order equations. Let y1= dy/dtand y2 = y, then: −−=−−=...
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This note was uploaded on 01/11/2011 for the course EE 3108 taught by Professor Nelsonszechunchan during the Spring '07 term at City University of Hong Kong.

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Tutorial08 - T8-1City University of Hong Kong Electronic...

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