EE3110 Bonus question 2_FR_2008_solution

EE3110 Bonus question 2_FR_2008_solution -...

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Bonus question 2 (23 rd  September 2008) due 4 th  October before the start of  lecture. Determine the low to mid-frequency response of the common collector  amplifier shown below. R B C 2 C 1 V C C v L v O v S R L R E R S The parameters for the common collector amplifier shown above are, R S 600 , R B =100k , R E =r π =R L =1k  and  β f =100. C 1  and C 2  are both 100 μ F. To  help you in your calculations state your assumptions where necessary and  make sure you include the following in your answers. a) The equivalent circuits at low frequency. b) The cut-off frequency(s) due to C 1 . b) The cut-off frequency(s) due to C 2 . c) The frequency response as seen at  v O . d) The frequency response as seen at  v L . e) The equivalent circuit at mid-frequency. Make sure that you mark down clearly the relevant details in you frequency  response.
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Solution a) Equivalent circuit at low frequency; Short circuit the supply voltage which 
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EE3110 Bonus question 2_FR_2008_solution -...

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