ansT3 - < ≤ − < ≤ − ≤ ≤...

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EE3118 Linear Systems and Signal Analysis KST SemA 2008/09 Answer of Tutorial 3 Q1. (a) T=4 and ω = π /2. (b) () = = + + + = 1 1 0 2 sin 2 cos n n n n t n b t n a a t x π where 8 3 0 = a , () = n n n a n cos 2 cos 2 2 2 and + = 2 sin 2 1 2 2 n n n b n Q2. () = = + + + = 1 1 0 2 sin 2 cos n n n n t n b t n a a t x where 75 . 1 0 = a , = ) cos( 4 3 cos 4 2 2 n n n a n and + == 2 3 sin 4 1 2 2 n n n b n Q3. (a) 60Hz and 120Hz (b) () −∞ = = n t jn n e c t x 240 where ) 4 1 ( 2 2 n c n = (c) 0 (d) 2 Q4. () −∞ = = n t jn n e c t x 240 where () [ ] 1 ) 1 ( 1 2 1 2 + = n n n c if 1 ± n and 4 1 j c m = ± Q5. (a) T=6 and ω = π /3. (b)
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Unformatted text preview: < ≤ − < ≤ − ≤ ≤ ≤ ≤ − − = 3 2 2 3 2 2 2 2 ) ( t or t t t t t t x (c) ( ) ∑ ∞ = + = 1 3 cos n n t n a a t x [Note: = n b because x(t) is even function] where 3 1 = a and + + = 3 2 cos 3 3 2 sin 2 3 2 2 2 2 n n n n n a n...
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