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Unformatted text preview: Exercise 3 Fix step iteration (4 marks) Consider following equation: (1) 1 3 2 = +x x and following two functions: (2) ( 29 ( 29 1 3 1 2 1 + = x x g and ( 29 x x g 1 3 2= a) Prove that (1) is equivalent to ( 29 x x g = 1 and as well equivalent to ( 29 x x g = 2 b) Plot the functions ( 29 x g 1 and ( 29 x g 2 for x between 0 and 5. x x y y c) Considering your figures from b), which one of the two functions ( 29 x g 1 and ( 29 x g 2 could you use to solve equation (1) using the fix point iteration method starting with 5 . 1 = o x ? Justify your answer by showing your iterations on your plots from figure b). d) For the function that you have chosen in c), solve equation (1) using the fix point iteration until you reach an answer with 4 significant digits ( 5 . 1 = o x ). Present your calculations in a table like : i i x ( 29 1 + i x g Error estimation 1.5 Answer:...
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 Spring '09
 HOIDICK
 Industrial Engineering

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